Question

A rocket rises vertically uo from the surface of the earth so that its distance varies from earth's surface as l=ct^2 where c is a constant. After 10 sec the rocket has travelled 2 km. Determine ots speed in m/s at that moment

Answer 1

Answer:

Explanation:

i=ct^2

v=2ct(differentiate the above eqn w.r.t. time)

when t=10 sec v=2*c*10=20c

c=i/t^2=2*10^3/100 =20

v=20*20=400m/s