A rod, 120cm long and of diameter 3.0 cm is subjected to an axial pull of 18 kN. The stress in N/mm2 is
Answers
25.47
hope you got the answer
Given info : A rod of 120 cm long and of diameter 3 cm is subjected to an axial pull of 18 kN.
To find : The stress in N/mm² is ...
solution : base area of rod, A = πd²/4 , where d is diameter of rod.
here, d = 3cm = 30 mm
so, A = π(30)²/4 = 900π/4 = 225π mm²
Stress = force applied/base area
= 18kN/225π mm²
= (18 × 10³)/(225 × 3.14) N/mm²
= 25.47 N/mm²
Therefore the stress acts on the rod is 25.47 N/mm²
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