A rod lies along the X-axis with one end at the origin and the other at x→∞. It carries a uniform charge λCm⁻¹. The electric field at the point x=-a on the axis will be
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Answer ⇒ E = kλ/a
Explanation ⇒ We know that if L is the length of the rod in which the charge is uniformly distributed as λ C/m.
Then, Electric field at an distance of l is given by the relation,
E = kλ[1/l - 1/(l + L)]
Now, here L = ∞, and l = a
∴ E = kλ[1/a - 0]
∴ E = kλ/a
Hence, the electric field on the negative x axis due to Uniform charge distribution of rod is kλ/a.
Hope it helps.
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