A rod of length 12 cm is placed horizontally along the optical axis of a concave mirror of focal length 24 cm. The end near to the pole is at the centre of curvature. Find the length of image of rod.
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Answers
Answer:
The object lies horizontally on the principal axis. So let the object be AB. B lies 20 cm away from the pole and A lies 10+20 = 30 cm away from the pole.
C = 2f = 2(10). Center of Curvature is 20 cm. So point B is at center of curvature and so the image formed will be 20 cm away from the mirror(in the left side). OR you can also verify this with mirror formula.
Image of Point A will be formed at = 1/v + 1/u = 1/f
1/v = 1/f - 1/u
1/v = 1/-10 -1/-30 = -2/20
v = -30/2 = -15.
So image of point A will be at 15 cm in left side of mirror. Now callculate the length of the image. It is equal to 20 - 15 = 5. Image distance of B - Image distance of A
Explanation:
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Answer:
hope this explanation is fine
Explanation:
The object lies horizontally on the principal axis. So let the object be AB. B lies 20 cm away from the pole and A lies 10+20 = 30 cm away from the pole.
C = 2f = 2(10). Center of Curvature is 20 cm. So point B is at center of curvature and so the image formed will be 20 cm away from the mirror(in the left side). OR you can also verify this with mirror formula.
Image of Point A will be formed at = 1/v + 1/u = 1/f
1/v = 1/f - 1/u
1/v = 1/-10 -1/-30 = -2/20
v = -30/2 = -15.
So image of point A will be at 15 cm in left side of mirror. Now calculate the length of the image. It is equal to 20 - 15 = 5. Image distance of B - Image distance of A