Question

factorise (p-q)^3 + (q-r)^3 + (r-p) ^3​

Answer 1

Answer:

Step-by-step explanation:

this is in the form of x^3 + y^3 + z^3 = 3xyz

which implies that   x+y+z = p-q-r+q-p+r

therefore x+y+z =0

x³ + y³ + z³ = 3xyz  

( p - q )³ + ( q - r )³ + ( r - p )³             {taking  3 as common}

= 3( p - q )( q - r )( r - p )    

Hence , This is the answer:

3*(q-p)*(r-p)*(r-q)