A rod of length 12cm moves with its ends always touching the coordinates axis Determine the equation of the locus of P on the rod Which is 3cm from the end in contact with x axis( With Diagram)
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Hey friend your answer is here
Given a rod of length 12 cm moves with its ends always touching the coordinate axes.
Again given a point P on the rod, which is 3 cm from the end in contact with the x-axis.
It is shown in the figure.

Here AP = 3 cm, AB = 12
Now BP = AB - AP
=> BP = 12 - 3
=> BP = 9 cm
Again from figure,
∠PAO = ∠BPO = θ (since PQ || OA and are corresponding angles)
Now in ΔBPO,
cosθ = QP/BP
=> cosθ = x/9 .............1
Again in ΔPAr,
sinθ = PR/PA
=> sinθ = y/3 ........2
Now square equation 1 and 2 and then add them, we get
cos2 θ + sin2 θ = x2 /81 + y2 /9
=> x2 /81 + y2 /9 = 1 (since cos2 θ + sin2 θ = 1 )
So the equation of the locus of a point P is x2 /81 + y2 /9 = 1
Given a rod of length 12 cm moves with its ends always touching the coordinate axes.
Again given a point P on the rod, which is 3 cm from the end in contact with the x-axis.
It is shown in the figure.

Here AP = 3 cm, AB = 12
Now BP = AB - AP
=> BP = 12 - 3
=> BP = 9 cm
Again from figure,
∠PAO = ∠BPO = θ (since PQ || OA and are corresponding angles)
Now in ΔBPO,
cosθ = QP/BP
=> cosθ = x/9 .............1
Again in ΔPAr,
sinθ = PR/PA
=> sinθ = y/3 ........2
Now square equation 1 and 2 and then add them, we get
cos2 θ + sin2 θ = x2 /81 + y2 /9
=> x2 /81 + y2 /9 = 1 (since cos2 θ + sin2 θ = 1 )
So the equation of the locus of a point P is x2 /81 + y2 /9 = 1
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riya462:
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hey this is ur answer with attached photo may help u
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