Question

A rod of length l and radius r is joined to a rod of length l/2 and radius r/2 of same material. The free end of small rod is fixed to a rigid base and the free end of larger rod is given a twist of θ°, the twist angle at the joint will be(a) θ/4(b) θ/2(c) 5θ/6(d) 8θ/48

Answer 1

Pta nii sorry.. Google

Answer 2

Answer:

Explanation:

Length of the rod = l (Given)

Radius of the rod = r (Given)

Length of the joined rod - l/2 (Given)

Radius of the joined rod = r/2 (Given)

Twist of the rod = θ° (Given)

Thus, as per the formula

τ = C.θ = πηr`4θ/2L = Constant

= πηr`4 (θ−θ0)/ 2l

= πη(r/2)`4 (θ0−θ′)/2(l/2)

= (θ−θ0)/2

= θ0/16

= θ0 = 8/9θ

Thus, the twist angle at the joint will be 8/9θ.