Two wires are made of the same material and have the same volume. However wire 1 has cross-sectional area A and wire 2 has cross-sectional area 3A. If the length of wire 1 increases by Δx on applying force F, how much force is needed to stretch wire 2 by the same amount?(a) 4 F(b) 6 F(c) 9 F(d) F
Answers
Answered by
39
Answer:
C) 9F
Explanation:
Since the two wires have the same volume. Thus,
Length of wire 1 =l
Length of wire 2 =l/3
Area of wire 1 =A
Area of wire 2 =3A
Wire 1 = F/A/ Δx/l
Wire 2 = F1/A/ Δx/l/3
Therefore,
F/A×l/Δx = F1/3A×l/3Δx
F1 = 9F
Thus, the force needed to stretch wire 2 by same amount is 9
Similar questions