Physics, asked by sakshi3378, 8 months ago

a rod of length l rotate in a vertical have a anglular plane velocity omega and angular acceleration alpha as shown in figure at the given instant ​

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Answers

Answered by Anonymous
1

Answer:

the fall of centre of mass

h=

2

L

(1−cosθ)

mgh=mg

2

L

(1−cosθ)

law of conservation of energy

2

1

2

=

2

mgl

(1−cosθ)

2

1

3

mL

2

ω

2

=

2

mgL

(1−cosθ)ω

2

2L

6g

=(1−cosθ)

2L

6g

2sin

2

2

θ

ω=

L

6g

sin

2

2

θ

ω=

L

6g

sin

2

θ

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