Physics, asked by vanshikathakur753, 8 months ago

a rod of magnetic material of cross section 0.25cm^2 is located in 4000am^-1 magnetising field . Magnetic flux passing through the rod is 25×10^-6wb.Find out magnetic susceptibility.​

Answers

Answered by lokhandegauri2006
2

Explanation:

  1. area A=0.25 cm2 =0.25*10^-4 m^2H=4000 A/m Flux =25*10^-6wb B= flux density =0/A B= 25*10^-6/0.25*10^-4 B=25×10^-6/ 25×10^-6. B=1.T B= uH u=B/H. =1/4000. u= 1/4×10^3 u=0.25×10^-3h/m
Answered by sandeshnirgude68
0

Explanation:

rod of magnetic material of cross section 0.25cm^2 is located in 4000am^-1 magnetising field . Magnetic flux passing through the rod is 25×10^-6wb.Find out magnetic susceptibility.

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