Math, asked by rajivahuja7216, 4 months ago

A rohmbus sheet whose perimeters 32mand whose one diagonalis 10 m long it painted on both sides at the rate ofrupee 5 per m sq find the coast of painting

Answers

Answered by itzAashish
6

Answer:

Perimeter = 32 m,

So, length of a side =32/4=8m,

and Diagonal of a rhombus = 10m,

As, we know that,

The halves of diagonals and a side of a rhombus from a right angled triangle with side as hypotenuse.

Let the length of the other diagonal =2x.

x

2

+(10/2)

2

=8

2

=x

2

+25=64

x

2

=64−25=39

x=

39

The measure of the another diagonal of the rhombus = 2*\sqrt { 39 } =2\sqrt { 39 } m

So, Area of the rhombus =1/2*Diagonal of a rhombus*Measure of the another diagonal

A=

2

1

×10×2

39

A=62.45m

2

painted on both sides at the rate of Rs 5 per m2

Cost = area of both side*5=2*62.45*5=624.50 Rs

Answer (B) Rs. 625

#HAVE A NICE DAY

Answered by vinaysindher
0

Answer:

Rs 624.45

Step-by-step explanation:

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