A rohmbus sheet whose perimeters 32mand whose one diagonalis 10 m long it painted on both sides at the rate ofrupee 5 per m sq find the coast of painting
Answers
Answered by
6
Answer:
Perimeter = 32 m,
So, length of a side =32/4=8m,
and Diagonal of a rhombus = 10m,
As, we know that,
The halves of diagonals and a side of a rhombus from a right angled triangle with side as hypotenuse.
Let the length of the other diagonal =2x.
x
2
+(10/2)
2
=8
2
=x
2
+25=64
x
2
=64−25=39
x=
39
The measure of the another diagonal of the rhombus = 2*\sqrt { 39 } =2\sqrt { 39 } m
So, Area of the rhombus =1/2*Diagonal of a rhombus*Measure of the another diagonal
A=
2
1
×10×2
39
A=62.45m
2
painted on both sides at the rate of Rs 5 per m2
Cost = area of both side*5=2*62.45*5=624.50 Rs
Answer (B) Rs. 625
#HAVE A NICE DAY
Answered by
0
Answer:
Rs 624.45
Step-by-step explanation:
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