a roller 140 cm long has a radius of 35 cm .to level the playground it takes 980 complete revolutions. determine the cost of levelling the playground at the rate of 75 paisa per square metre.
Answers
Answered by
11
first we need to find the surface area of the roller
LSA=2πrh
=2x22÷7x35x140 =30800cm^2 or 3.08m^2
so 1 revo = 30800cm
980 = ?
30800x980=
30184000cm^2 or
3018.4m^2
so 3018.4x75=226380 or ₹ 2263.80
LSA=2πrh
=2x22÷7x35x140 =30800cm^2 or 3.08m^2
so 1 revo = 30800cm
980 = ?
30800x980=
30184000cm^2 or
3018.4m^2
so 3018.4x75=226380 or ₹ 2263.80
Siddhu2002:
m^2 means square metre
Answered by
2
Surface area of roller=2πrl
=2π×35×140
30787
Total area=30787*980
30171855
Cost 0.75*30181855
Rs22628891
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