a roller 140 cm long has a radius of 35 cm .to level the playground it takes 980 complete revolutions. determine the cost of levelling the playground at the rate of 75 paisa per square metre.
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Answered by
11
first we need to find the surface area of the roller
LSA=2πrh
=2x22÷7x35x140 =30800cm^2 or 3.08m^2
so 1 revo = 30800cm
980 = ?
30800x980=
30184000cm^2 or
3018.4m^2
so 3018.4x75=226380 or ₹ 2263.80
LSA=2πrh
=2x22÷7x35x140 =30800cm^2 or 3.08m^2
so 1 revo = 30800cm
980 = ?
30800x980=
30184000cm^2 or
3018.4m^2
so 3018.4x75=226380 or ₹ 2263.80
Siddhu2002:
m^2 means square metre
Answered by
2
Surface area of roller=2πrl
=2π×35×140
30787
Total area=30787*980
30171855
Cost 0.75*30181855
Rs22628891
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