Question

A roller takes 500 complete revolution to level a playground find the cost of levelling the ground at the rate of 75 paise per sq meter if the diameter and length of the roller are 84 cm and 120 cm respectively ​

Answer 1

Answer:

A roller takes 500 complete revolution to level a playground find the cost of levelling the ground at the rate of 75 paise per sq meter if the diameter and length of the roller are 84 cm and 120 cm respectively

Step-by-step explanation:

224

Answer 2

Given:-

★ A roller takes 500 complete revolutions to level a playground.

★ Length of roller (l) = 120 cm =1.2 m

★Diameter of roller (d) = 84 cm = 0.84 m

To Find :-

★ What is the cost of levelling the ground?

Solution :-

Given that,

Diameter of roller (d) = 0.84 m

Therefore,

Radius = Diameter /2

⟹ Radius = 0.84/ 2

⟹ Radius = 0.42 m

We know,

☞ CSA of roller area = 2πrh

Substituting the values, we get

CSA of roller area = 2πrh

= 2 ×3.1416 × 0.42 × 1.2

= 3.168 m²

Hence,

Area levelled by roller in 1 revolution = 3.168 m²

Area levelled by roller in 500 revolution

=500 × 3.168 m²

= 1584 m²

Therefore,

cost of levelling at 0.75 per m²

= 0.75 × 1584

= 1188

Hence,

The cost of levelling the ground is = 1188

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