Question

A roller takes 750 complete revolutions to move once over a level of road. Find the area of road if the diameter of the roller is 85 cm and length is 1 m.

Answer 1

Answer:

CSA of roller=2×22/7×100×85/2=26714.28cm^2

. =2.6714m^2

Area of road=2.6714×750=2003.55m^2

Answer 2

Solution:-

Given:-

• Diameter of roller = 84 then radius = 84/2 = 42 or 0.42 m
• and ,height = 1 m

Explaination:-

• In one revolution, the road roller will cover an area equal to its lateral surface area.

So, in one revolution the area of the road covered = 2πrh

= 2 × $\frac{22}{7}$ × 0.42 × 1

Area of the road in one revolution = 2.64 sq m

Therefore, in 750 revolutions, the area of the road = 2.64 × 750

= 1980 sq m

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Hope it helps buddy : )