A room 11m * 8m * 5m. Find the cost of cementing its four walls and floor at the rate of ₹4 per square metre including doors and windows etc.
Answers
Answered by
52
Hey,
l = 11 m
b = 8 m
h = 5 m
top of the room = lb
= 11 × 8
= 88 m
TSA of the cuboid = 2(lb + bh + hl)
=2(11×8 +8×5 + 5×11)
=2(183)
= 366 m²
what we want the by question = 366 - 88
= 278 m
floor at the rate of the rs.4 = 278 × 4
=1112 rupees
HOPE IT HELPS:-))
l = 11 m
b = 8 m
h = 5 m
top of the room = lb
= 11 × 8
= 88 m
TSA of the cuboid = 2(lb + bh + hl)
=2(11×8 +8×5 + 5×11)
=2(183)
= 366 m²
what we want the by question = 366 - 88
= 278 m
floor at the rate of the rs.4 = 278 × 4
=1112 rupees
HOPE IT HELPS:-))
aakarshguptaknpes5p1:
Thank you bro
Answered by
13
Step-by-step explanation:
this is answer
mark brainliest
Attachments:
Similar questions