A room 57m 80cm long amd 47m 60cm broad is to be paved with equal square tiles find the largest tile so that the tile
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length of the room= 57 m ie 5700cm +80cm
=5780cm
breadth of the room=47m ie 4700cm +60cm
4760cm
hence, Area of the room surface= length×breadth
= 5780×4760
=27512800 cm^2
Here is your answer the largest tile. needed for flooring should have area of 2751800 cm^2
=5780cm
breadth of the room=47m ie 4700cm +60cm
4760cm
hence, Area of the room surface= length×breadth
= 5780×4760
=27512800 cm^2
Here is your answer the largest tile. needed for flooring should have area of 2751800 cm^2
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Answer: Dimension of largest square tile = 340 * 340 cm
Step-by-step explanation:
Given, Length of room = 57m 80cm = 5780 cm
Breadth of room = 47 m 60 cm = 4760 cm
[ ∵ 100 cm = 1 m]
⇒ Factors of 5780 = 2*2*5*17*17
⇒ Factors of 4760 = 2*2*2*5*7*17
∴ H.C.F of 5780 and 4780 = 340
∴ Dimension of largest square tile = 340 * 340 cm
∴ Area of largest square tile = 115600
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