Math, asked by sourabhsoni501, 1 year ago

a room 5m long .4.5 m wide and 3.6m high has one door 1.5 m bg 2.4 m and two windowa each 1m by 0.75m.find:1.the area of its wls , excluding doors and windows.2.the cost of disterpering its walls at the rate of ₹4.50 per msq. 3 the cost of painting its roof at the rate of ₹9 per msq.

Answers

Answered by medeni
44
1)  the area wall= curved surface area of room - area of 2 window- area of door
 curved surface area of room = 2h (l+b) 
= 2 x 3.6 ( 5 + 4.5) = 7.2 x 9.5
= 68.4 m^2
area of two window= 2 x ( l x b)
= 2 x 1 x 0.75
=1.5 m^2
area of door = l x b
= 1.5 x 2.4 
3.6 m^2
area of wall = 68.4 - 1.5 - 3.6
                   = 63.3 m ^2
2) the cost of disterpering =  63.3 x 4.5
                                          = Rs 284.85

3) the cost of painting roof= l x b
 5 x 4.5 = 22.5 m^ 2
cost = 22.5 x 9 
        = Rs 202.50









 
 

Answered by nivajain4
6

Answer:

Step-by-step explanation:

1)  the area wall= curved surface area of room - area of 2 window- area of door

curved surface area of room = 2h (l+b)  

= 2 x 3.6 ( 5 + 4.5) = 7.2 x 9.5

= 68.4 m^2

area of two window= 2 x ( l x b)

= 2 x 1 x 0.75

=1.5 m^2

area of door = l x b

= 1.5 x 2.4  

3.6 m^2

area of wall = 68.4 - 1.5 - 3.6

                  = 63.3 m ^2

2) the cost of dis tempering =  63.3 x 4.5

                                         = Rs 284.85

3) the cost of painting roof= l x b

5 x 4.5 = 22.5 m^ 2

cost = 22.5 x 9  

       = Rs 202.50

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