Question

A room 9.5 m long and 6 m wide is surrounded by a varandah 1.25 m wide.calculate the cost of cementing the floor of this verandah at rupees 28 per sq.meter.

Answer 1

Area of room =6×9.5m = 57m
length of varandah=9.5m+1.5+1
5=12.5m
breath = 6+1.5+1.5=9m
area of big room=9×12.5=112.5
area of varanda=112.5-57m=
54.5m ANS

Answer 2

✬ Cost = Rs 1260 ✬

Step-by-step explanation:

Giveb:

• Length and Breadth of room is 9.5 m and 6 m respectively.
• Width of veranda is 1.25 m.
• Cost of cementing is 28 / m²

To Find:

• What is cost of cementing the floor of veranda ?

Solution: Let ABCD be a rectangular room surrounded by EFGH.

★ In rectangle ABCD ★

• Length = AB = 9.5 m
• Breadth = BC = 6 m

★ Area of rectangular room =Length x Breadth★

$\small\implies{\sf }$ Area of ABCD = AB X BC

$\small\implies{\sf }$ Area of ABCD = (9.5 x 6 ) m²

$\small\implies{\sf }$ Area of ABCD = 57 m²

★ In rectangle EFGH ★

• Length = EF = (AB + 1.25 + 1.25)

• EF = ( 9.5 + 1.25 + 1.25) = 12 m

• Breadth = FG = (BC + 1.25 + 1.25)

• FG = (6 + 1.25 + 1.25) = 8.5 m

∴ Area of EFGH = EF x FG

$\small\implies{\sf }$ Area of EFGH = (12 x 8.5) m²

$\small\implies{\sf }$ Area of EFGH = 102 m²

★ If we subtract the area of ABCD from the area of EFGH, we will get the area of veranda ★

$\small\implies{\sf }$ Area of veranda = Area ( EFGH – ABCD)

$\small\implies{\sf }$ Area of veranda = (102 – 57) m²

$\small\implies{\sf }$ Area of veranda = 45 m²

Hence, the area of veranda is 45 m²

→ Cost of cementing 1 m² floor of veranda = Rs 28

∴ Cost of cementing 45m² floor of veranda = Rs ( 28 x 45) = Rs 1260

Hence, Cost of cementing the floor of veranda is Rs 1260.