Question

A room has 3 lamps from a collection of 10 light bulbs of which 6 are not good a person select 3 at random and puts

Answer 1

total no. of events == no. of selecting 33 lamps out of total 1010 is (103)(103)

Now favourable events == selecting 33 bulbs out of total 44 blubs =(43)=(43)

So Required probability =4⋅3⋅210⋅9⋅8=130=4⋅3⋅210⋅9⋅8=130

Is my solution is right, If not then how can we solve it,