A room has a floor measuring 15 m by 8m . it has to be covered with tiles of size 50 cm by 25 cm .how many tiles are required? If a carpet is laid on the floor so that a space of 1.5 m is left around the edges of floor, what fraction of the floor is uncovered?
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Answered by
30
NO. OF TILES
= AREA OF FLOOR ÷ AREA OF 1 TITLE
= (15 M × 8 M) ÷( 50CM × 25 CM )
=( 1500CM × 800CM ) ÷ (50CM × 25 CM)
= 1200000÷1250
=960 titles
length of carpet = 15 -1.5 -1.5 = 12 m
breadth of carpet = 8 -1.5 -1.5= 5 m
so area of carpet = 12×5 = 60 m2
so uncovered floor = 15×8 - 60
= 120 - 60 = 60m2
SO FRACTION OF FLOOR UNCOVERED
= 60/120
= 1/2
= AREA OF FLOOR ÷ AREA OF 1 TITLE
= (15 M × 8 M) ÷( 50CM × 25 CM )
=( 1500CM × 800CM ) ÷ (50CM × 25 CM)
= 1200000÷1250
=960 titles
length of carpet = 15 -1.5 -1.5 = 12 m
breadth of carpet = 8 -1.5 -1.5= 5 m
so area of carpet = 12×5 = 60 m2
so uncovered floor = 15×8 - 60
= 120 - 60 = 60m2
SO FRACTION OF FLOOR UNCOVERED
= 60/120
= 1/2
Answered by
8
no of tiles = 960
fraction of uncovered floor is 1/2
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