A room heater is rating 500 w 220v find the resistance of coil
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Answered by
6
Given,
Rating of the room heater = 500 W
Potential difference across the heater = 220 V
The power rating of an electric appliance is the electrical energy consumed per second by the appliance when connected across the marked voltage of the mains.
P =
on putting the values,
R = 22* 22 / 5
R = 484 / 5
R = 96.8 ohm.
Thus, the resistance of the coil is 96.8 Ohm.
Answered by
4
Answer: 96.8 Ω
Explanation:
Given,
P = 500 W
Voltage (V) = 220 Volt
Resistance of the coil (R) = ?
We know that,
For any circuit,
P = Vi × cosФ
Where Ф is phase difference between V and i.
Since, this heater is treated as pure ohm's circuit. Therefore Ф=0
cosФ = cos0° = 1
So,
P = Vi
Again using ohm's law,
Putting i = V/R
P = V²/R
500 = (220×220)/R
R = (220×220)/500
R = (22×22)/5
R = 484/5
R = 96.8 Ω
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