A room is 18m long 4m wide, It's floor is to be covered with rectangular tiles of size 9cm by 8cm. Find the cost of tiles at 5.25 per tile.
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Length of room = 18m
Breadth of room = 4m
Area = 2 × ( L + B )
= 2 × (18 + 4)
= 2 × 22 = 44 m² = 4400 cm²
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Length of tile = 9cm
Breadth of tile = 8cm
Area = 2 × (L+B)
= 2 × (9+8)
= 2 × 17
= 24cm²
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Number of tiles that will be placed =
4400/24 = 183.3 tiles
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Cost per tile = ₹5.25
Cost of 183.3 tiles = 5.25 × 183.3 = ₹962.3
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