A room is 4.5 m long and 4 m wide. The floor of the room is to be covered with tiles of size 15 cm by 10 cm.Find the cost of covering the floor with tiles at the rate of 4.50per tile
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Answer:
Given, Length of room =4.5m and breadth of room =4 m
So, Area of room =4.5×4=18 m^2
Area of room =18×(10000 cm^2) =180000
Size of tiles =(15 cm×10 cm)
So, Area of tile one =15×10=150 cm
So, number of tiles required to cover the floor=
Area of floor/Area of one tile = 180000/150=1200
It is given that for one tile it costs Rs. 4.50
Therefore. cost of covering the floor with tiles
=4.60*1200= Rs5400
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