A room is 4.5m long, 3m wide and 2.8m high. It has one door 1.4m wide and 2m high and two rectangular windows each of 2m long and 1.5m wide. Find the cost of white washing the inner four walls at 100/-/m²
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Area to be white washed= Area of room - Area of door+ Area of two windows
Area of room = 2(lb+bh+lh)
= 2× (4.5× 3 + 3×2.8+4.5×2.8)
= 2× ( 13.5 + 8.4+12.6)
= 2×34.5
= 69 m sq.
Area of door -
=l×b
=1.4×2
=2.8 m sq.
Area of windows=
= l×b×2
=2×1.5×2
=6 m sq.
Therefore, Area to be white washed= 69-(2.8+6)
=69-8.8
= 60.2 m sq.
Cost of white washing = 60.2 × 100
= 6020 rupees Ans
Welcome in advance
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Area of room = 2(lb+bh+lh)
= 2× (4.5× 3 + 3×2.8+4.5×2.8)
= 2× ( 13.5 + 8.4+12.6)
= 2×34.5
= 69 m sq.
Area of door -
=l×b
=1.4×2
=2.8 m sq.
Area of windows=
= l×b×2
=2×1.5×2
=6 m sq.
Therefore, Area to be white washed= 69-(2.8+6)
=69-8.8
= 60.2 m sq.
Cost of white washing = 60.2 × 100
= 6020 rupees Ans
Welcome in advance
pls mark this as the brainliest answer.:D
himanshi8229:
that's a wrong answer The right answer is 3320/-
Ok, but what's the mistake, pls tell
leave it , got it
I thought all 6 walls
Just find the area of 4 walls by 2×(bh+hl) And subtract 8.8 from it instead
Sorry for the confusion
yes then it will come 3320
ok
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