a room is 6 metre long,5 metre broad and 4 metres high .it has two doors, each measuring 1.5 m by 2m, and four windows each measuring 1 by 1 m. find the cost of distempering the walls at ₹25/m²
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Hi Dear !
The Room Dimensions are :
Length = 6 m
Breadth = 5 m
height = 4 m
LSA of cuboid = 2h(l+b)
= 2 x 4(6 + 5) = 8 x 11 = 88 m²
Dimensions of one of the door
height = 2 m
length = 1.5 m
Area of two doors = 2 x 2 x 1.5 = 6 m²
Dimensions of one of the window
height = 1 m
length = 1 m
Area of four windows = 4 x 1 x 1 = 4 m²
Area to be distempered = 88 - 6 - 4 = 78 m²
Cost of distemper = 25 x 78 = ₹ 1950
The Room Dimensions are :
Length = 6 m
Breadth = 5 m
height = 4 m
LSA of cuboid = 2h(l+b)
= 2 x 4(6 + 5) = 8 x 11 = 88 m²
Dimensions of one of the door
height = 2 m
length = 1.5 m
Area of two doors = 2 x 2 x 1.5 = 6 m²
Dimensions of one of the window
height = 1 m
length = 1 m
Area of four windows = 4 x 1 x 1 = 4 m²
Area to be distempered = 88 - 6 - 4 = 78 m²
Cost of distemper = 25 x 78 = ₹ 1950
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The answer is rupees 3450
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no but thnks for helping
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