Question

A room is 8.60 long and 6.25 meters wide its floor is to covered with the designer tiles of size 20 cm into 10 cm find the total cost of tiles is the cost of one tile is rupees one hundred

Answer 1

Answer:

14875

Step-by-step explanation:

Correct option is

D

Rs. 14875

Area of room → Length X Breadth

Area of room  → 1150 ×630  → 724500 sq. cm

Area of 1 tile → 23×9  → 207 sq. cm

Number of tiles required  → Area of tileArea of room

Number of tiles required  → 207724500  → 3500

Cost of tiling  → (Number of tiles) × (Cost of 1 tile)  → 3500×4.25  → 14875

Answer 2

☘️ Solution :

Length of the room = 8.60 m or (8.60 × 100) cm = 860 cm

Breadth of the room = 6.25 m or (6.25 × 100) cm = 625 cm

Size of each tile = 20 cm × 10 cm

Area of each tile = (20 × 10) sq cm

Number of tiles required for flooring

$\\ =\sf \: \frac{Area~~ of~~the~~ floor}{Area~~ of~~ each \: \: tile \: } \\ \\ \sf = \frac{860 \times 625}{20 \times 10}$

Cost of each tile = ₹100

Total cost of titles

$\\ \sf \: = \frac{ \cancel{860} {}^{430} \times 625 \times1 \cancel{00} }{ \cancel{2} {}^{1} \cancel{0} \times 1 \cancel{0}} \\ \\ \large \sf = \purple{₹2,68,750}$

Therefore, the total cost of titles = ₹2,68,750