Question

a room is 8.60 m long and 6.25 m broad . its is to be covered with tiles if 20 cm and 10 cm . find the total cost of tiles . if the cost of 1 tile is 100
pls
pls
explain​

Answer 1

Answer:

Correct option is

D

Rs. 14875

Area of room → Length X Breadth

Area of room → 1150 ×630 → 724500 sq. cm

Area of 1 tile → 23×9 → 207 sq. cm

Number of tiles required →

Area of tile

Area of room

Number of tiles required →

207

724500

→ 3500

Cost of tiling → (Number of tiles) × (Cost of 1 tile) → 3500×4.25 → 14875

Answer 2

☘️ Solution :

Length of the room = 8.60 m or (8.60 × 100) cm = 860 cm

Breadth of the room = 6.25 m or (6.25 × 100) cm = 625 cm

$\begin{gathered}\\\end{gathered}$

Size of each tile = 20 cm × 10 cm

Area of each tile = (20 × 10) sq cm

$\begin{gathered}\\\end{gathered}$

Number of tiles required for flooring

$\begin{gathered} \\ =\sf \: \frac{Area~~ of~~the~~ floor}{Area~~ of~~ each \: \: tile \: } \\ \\ \sf = \frac{860 \times 625}{20 \times 10} \\ \\ \end{gathered}$

Cost of each tile = ₹100

$\begin{gathered}\\\end{gathered}$

Total cost of titles

$\begin{gathered} \\ \sf \: = \frac{ \cancel{860} {}^{430} \times 625 \times1 \cancel{00} }{ \cancel{2} {}^{1} \cancel{0} \times 1 \cancel{0}} \\ \\ \large \sf = \purple{₹2,68,750} \\ \\ \end{gathered}$

Therefore, the total cost of titles = ₹2,68,750