Question

a room is 8 m long,9 m broad and 6 m high.it has two doors each measuring 2.5m*1.5m and four windows each of size 1.2m*1m. find the cost of White washing the walls of the room at the rate of rupees 2.00per sq. m.​

Answer 1

Answer:

according to question :-

TSA (total surface area) of room = 2(lh+bh+lb)

TSA = 2(8*6+9*6+8*9)

TSA = 2(48+54+72) = 2*174 = 348m^2

now area of two doors = 2(2.5+1.5) = 2*4 = 8 m^2

and area of 4 windows = 4(1.2+1)= 4*2.2 = 8.8m^2

now area of the walls excluding walls and windows :-

348-8-8.8 = 348.0-16.8 = 331.2m^2

now if

1m^2 = ₹2

then 331.2 = 2*331.2 = ₹662.4

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