Math, asked by rush9940, 6 months ago

A Room. Is. 8m. Long and. 6m. Wide. It's. Floor. Is. To. Be. Covered with. Rectangular. Tiles. Of. Size. 25 cm. By. 20cm. how. Many. Tiles. Will. Be. Required. ?find. The. Cost. Of. These. Tiles. At. Rs. 25 per. Tiles

Answers

Answered by divyamJoshi
4

Answer:

14875

Step-by-step explanation:

Area of room → Length X Breadth

Area of room → 1150 ×630 → 724500 sq. cm

Area of 1 tile → 23×9 → 207 sq. cm

Number of tiles required →

Area of tile

Area of room

Number of tiles required →

207

724500

→ 3500

Cost of tiling → (Number of tiles) × (Cost of 1 tile) → 3500×4.25 → 14875

Answered by Apeksha1804
4

Answer:

960 tiles

Rs. 24000

Step-by-step explanation:

length of floor = 8 m = 800 cm

width of floor = 6 m = 600 cm

Area of floor = 800 cm × 600 cm

= 480000 cm²

Area of tile = 25 cm × 20 cm

= 500 cm²

Number of tiles required = Area of floor

__________

Area of tile

= 480000/ 500

= 960 tiles

Cost per tile = Rs. 25

Hence total cost = 960 × 25

= Rs. 24000

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