Question

The hero of a stunt film fires 50 g bullets from a machine
gun, each at a speed of 1.0 km/s. If he fires 20 bullets
in 4 seconds, what average force does he exert against
the machine gun during this period ?​

Answer 1

Answer:

The momentum of each bullet,

= (0.050kg)(1000m/s)= 50kg-m/s

thus, the rate of of change of momentum of the gun ,

$= > \: \frac{50 \times 20}{4s}$

$= > 250newton$

Answer 2

Explanation:

The hero of a stunt film fires 50g bullets form a machine gun, each at a speed of 1.0km/s. If he fires 20 bullets in 4s, what average force does he exert against the machine gun during this period? Solution : The momentum of each bullet (0.050kg)(1000m/s)=50kgm/s.