Math, asked by mohdtauheed121212, 2 months ago

A room which is 40m long and 15m broad is to be paved with tiles,each measuring 6cm by 5cm. Find the number of tiles required. Please solve step by step..​

Answers

Answered by DeepaliDhiwar
2

length of room = 40m

breath of room = 15m

area of room = l × b

= 40×15 = 600m square

length of tile = 6cm

breadth of tile =5cm

area of tile =30Cm

(1 m = 100 cm ) so 600m = 60000cm

tiles required = 60000/30

=2000

hope it will be helpful for you ❤️

Answered by Jyotu1972
0

Answer:

2000 tiles required.

Step-by-step explanation:

Length of room = 40 m

Breadth of room = 15 m

Area = l × b

= 40 × 15 m

40 m = 40000 cm.

15 m = 15000 cm

= 40000 × 15000

60000000 cm²

Area of room is 60000000 m².

length of tile = 6 cm

breadth of tile = 5 cm

Area = l × b

= 6 × 5 cm

= 30 cm²

Area of tile is 30 cm².

No. of tiles needed for covering the room is ==

( 60000000 m²÷ 30 cm² )

= 2000

2000

hence the numbers of tiles needed are 2000.

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