Question

A room without ceiling is 12m long, 4m wide and 3m high.find the length of the longest rod that can be placed in that room.​

Answer 1

Answer:

length of the longest rod = diagonal of the room

=> diagonal =

$\sqrt{ {w}^{2} + {l}^{2} + {h}^{2} }$

=> diagonal = √ 4^2+ 12^2+3^2

=> diagonal = √16+144+9

=> diagonal = √169

=> diagonal = 13. Answer

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Answer 2

Longest rod of 13 meter can be placed in that room

Step-by-step explanation:

Length of the room = 12 meter

Breadth of the room = 4 meter

height of the room = 3 meter

Longest rod that can be placed in that room (cuboid) is diagonally.

Length of diagonal of a cuboid = $\sqrt{(l^2+b^2+h^2)}$

= $\sqrt{(12^2+4^2+3^2)}$

= $\sqrt{(144+16+9)}$

= $\sqrt{169}$

= 13 meter

Longest rod of 13 meter can be placed in that room.

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