Question

a roommate 4.8 metre long and 3.2 metre by its floor is to be constructed with square marble tiles of Daimantion 8 cm into 8 cm find the number of tiles required to cover the floor and the cost of the tiles at rupees 15 per dozen ​

Answer 1

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A room floor is of 4.8 metre long and 3.2 metre in breadth .Now the floor is to be constructed with square marble tiles of dimension( 8 cm × 8 cm), find the number Number of tiles required to cover the floor and the cost of the tiles at a rate of rupees 15 per dozen .

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❍Let'S Head to the Problem Now

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$\huge \star$ For the Room Floor :-

$\rightarrow$ length(l)=4.8 metres.

$\rightarrow$ breadth(b)=3.2 metres.

$\therefore$ Area=(l×b)=(4.8×3.2)m²

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$\huge \star$ For Each Marbel tile :-

$\rightarrow$ side(a)=8 cm=0.08 m

$\therefore$ Area=(d²)=(0.08×0.08)m²

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$\huge \star$ Finding Number of Tiles :-

$\implies \boxed{ \red{\bf No.Of .Tiles= \frac{Area\: Of\: floor}{Area\: of\: each \:Tile}}}\\</p><p>\implies \bf No.Of .Tiles=\frac{4.8\times 3.2}{0.08\times 0.08}\\ \implies \bf No.Of .Tiles=\frac{4.8\times 3.2\times100\times100}{8\times 8}\\ \implies \bf No.Of .Tiles=\frac{\cancel{48}\times \cancel{32}\times100}{\cancel8\times \cancel8}\\ \implies \bf No.Of .Tiles=(6\times4\times100)\\ \implies \boxed{\red{\bf No.Of .Tiles=2400\:pcs.}}$

$\therefore$Number Of Tiles=2400 pcs

Now, Given that the cost of the tiles at rupees 15 per dozen .

$\bf\therefore cost\: of \:the \:Tiles\: =\frac{15}{\cancel{12}}\times\cancel{2400}\\ \implies\bf\therefore cost \:of \:the \:Tiles = 15\times200 \:Rs\\ \implies\bf\therefore \boxed{ \bf\red{cost\: of \:the\: Tiles =30000\:Rs}}$

$\therefore$Cost Of Tiles=30,000 Rs

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