A root of the equation x3 - x - 11 = 0 using bisection method is
Answers
Given : x³ - x - 11 = 0
To Find : a root by bisection method
Solution:
x³ - x - 11 = 0
f(0) = - 11
f(1) = - 11
f(2) = -5
f(3) = 13
one root lies between 2 & 3
(2 +3 )/2 = 2.5
f(2.5) = 2.125
0 lies between -5 & 2.125
Hence (2 + 2.5)/2 = 2.25
f(2.25) = -1.859375
(2.25 + 2.5)/2 = 2.375
f(2.375) = 0.021484375
f(2.3125) = -0.946044922
f(2.34375)= -0.469146729
f (2.359375) = -0.225559235
f(2.3671875)= -0.102470875
f(2.37109375) -0.04060179
f(2.373046875) = -0.009585865
f(2.374023438)= 0.005942463
f(2.373535156) = -0.001823399
f(2.373779297) = 0.002059108
f(2.373657227)= 0.000117748
f(2.373596191 ) = -0.000852852
f(2.373626709) = -0.000367558
f(2.373641968) -0.000124907
f(2.373649597) -3.57949E-06
f(2.373653412) 5.70844E-05
f(2.373651505) 2.67524E-05
2.37365 is a root
Learn More:
Use bisection method to find root of the equation x3 – 2x – 5 = 0 ...
https://brainly.in/question/6242554
Find the root of the equation x^3-2x-5= 0 by Bisection method ...
https://brainly.in/question/18811634