A rope can form an equilateral triangle of side 44 cm.If this rope can be wrapped around a cylinder exactly two times.Find the diameter of the cylinder.(take pie as 22/7)
Answers
Answered by
1
Answer:
2x22/7xr = 66
r. = 66x7/44
r. = 21/2
d. = 21
Answered by
1
Answer:
21cm
Step-by-step explanation:
perimeter of equilateral triangle= 3 side
3×44. = 132cm
ATQ. 2× circumference of cylinder. =132 cm
2 ×2πr =132
2× 2× 22/7 ×r = 132
88/7 × r = 132
r = 132× 7/88. = 21/2 cm
diameter = 2× radius
2 × 21/2 = 21 cm
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