Question

find the value of x if
${2}^{11 } \div {2}^{5} = {2}^{ - 3} \times {2}^{2x - 1}$
please tell the answer fast​

Answer 1

Step-by-step explanation:

$\huge \mathfrak \green{Answer}$

${2}^{11} \div {2}^{5} = {2}^{ - 3} \times {2}^{2x - 1}$

$log_{2} ({2}^{11} ) + log_{2}(1) - log_{2} ({2}^{5} )$

$= log_{2}( {2}^{ - 3} ) + log_{2}( {2}^{2x - 1} )$

$x = 5$