Question

A rope is wound around a uniform cylinder of mass 6kg​

Answer 1

Answer:

here your answer in given picture....

Answer 2

HELLO DEAR,

QUESTION:- A rope is wound around a uniform solid cylinder of mass 6 kg and radius 80cm. The rope is pulled with a force F such that angular acceleration of the cylinder is 10rad/s2. the value of F is

GIVEN:- Mass of uniform solid cylinder (M) = 6 kg

Radius of uniform solid cylinder (R) = 80cm = 0.8 m

Angular acceleration of uniform solid cylinder ( α) = 10 rad/s²

To find the linear force deliverd by rope on the uniform solid cylinder (F) .

SOLUTION:- we Know that ,

I = MR²/2 ( moment of inertia for uniform solid cylinder)

And l = τ/α

τ =lα. (1) ( τ= torque, α = angular acceleration)

And also ,

τ = F×R (2)

So, from (1) and (2)

F×R = lα

F× R = MR²α/2

F = MR²α/2R

F = MRα/2

F = (6×0.8×10) / 2

F = 48 / 2

F = 24 N

I HOPE IT'S HELP YOU DEAR,

THANKS.