Question

a rope is wound around a uniform solid cylinder of mass 6 kg and radius 80cm. The rope is pulled with a force F such that angular acceleration of the cylinder is 10rad/s2. the value of F is
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Answer 1

Explanation:

Pls find the attachment....

Answer 2

HELLO DEAR,

GIVEN:-

Mass of uniform solid cylinder (M) = 6 kg

Radius of uniform solid cylinder(R)= 80 cm = 0.8 m

Angular acceleration of uniform solid cylinder (α)= 10 rad/s².

To find the linear force (F) that delivered by rope on uniform solid cylinder.

SOLUTION:- we know that ,

I = MR²/2 ( l = moment of inertia of uniform solid cylinder)

And l = τ/α

τ = lα ------------(1) ( τ = torque, α = angular acceleration)

τ = F × R -------------(2) ( F = linear force, R = radius of uniform cylinder)

From (1) and (2) we get,

F × R = lα

F = lα/R

F = MR²α/2R

F = MRα/2

F = (6 × 0.8 × 10)/2

F = 48/2

F = 24 N .

I HOPE IT'S HELP YOU DEAR,

THANKS.