A rope of length 10 meter 20 centimeter is to be divided into three pieces whose lengths are in ratio 4:6:7. Find the length of each piece
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Answered by
28
given the length of the rope = 10m and 20cm
we know that 1m = 100cm
therefore 10m = 100 × 10 = 1000cm
total length of the rope = 1000 + 20
= 1020cm
according to the question, the rope is divided in three pieces whose length are in ratio 4 : 6 : 7
let the pieces be 4x, 6x and 7x respectively.
therefore 4x + 6x + 7x = 1020cm
>> 17x = 1020cm
>> x = 1020/17
>> x = 60cm
hence, the length of each piece is :-
>> 4x = 4 × 60 = 240cm
>> 6x = 6 × 60 = 360cm
>> 7x = 7 × 60 = 420cm
Answered by
1
Step-by-step explanation:
given the length of the rope = 10m and 20cm
we know that 1m = 100cm
therefore 10m = 100 × 10 = 1000cm
total length of the rope = 1000 + 20
= 1020cm
according to the question, the rope is divided in three pieces whose length are in ratio 4 : 6 : 7
let the pieces be 4x, 6x and 7x respectively.
therefore 4x + 6x + 7x = 1020cm
>> 17x = 1020cm
>> x = 1020/17
>> x = 60cm
hence, the length of each piece is :-
>> 4x = 4 × 60 = 240cm
>> 6x = 6 × 60 = 360cm
>> 7x = 7 × 60 = 420cm
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