Question

A rotating shaft carries four masses A, B, C and D, which are radially attached to it. The mass centers are 30 mm, 38 mm, 40 mm and 35 mm respectively from the axis of rotation. The masses A, C and D are 7.5 kg, 5 kg and 4 kg respectively. The axial distance between the planes of rotation of A and B is 400 mm and between b and c is 500 mm. The masses A and C are at right angles to each other. Find for a complete balance, (1) The angle between the masses B and D from mass A, (2) The axial distance between the planes of rotation of C and D, (3) The magnitude of mass D.

Answer 1

Answer:

The Answer Is "2"

Explanation:

there is so many axial distance between the planes of rotation of card c and d

Answer 2

Answer:

(1) The angle between the masses B and D from mass A is 192°

(2) The axial distance between the planes of rotation of C and D is 355 mm

(3) The magnitude of mass D = 316° counterclockwise from mass mA. (i.e. 7.5 kg).

Explanation:

Draw the pair polygon first using the information from column 1 of Table  at an appropriate scale. Given that the proportion of the balanced pair to 0.152X is known as the measurement,

X = 0.855 m  

0.152X = vector b = 0.13 $kg-m^{2}$.

The axial separation between the rotational axes of C and D is

(855 - 500)mm = 355 mm.

According to measurements, the angle of mD is

D = 360° - 44° = 316° counterclockwise from mass mA. (i.e. 7.5 kg).

Now, create the force polygon as depicted in Fig. 1.14 using the information from Table 1.6's column 5. (b). The balanced force is represented by the vector co. Since the balanced force is inversely proportional to 0.04 mB, mB = vector co = 0.34 kg-m, or 8.5 kg, may be calculated by measurement.

According to measurements, the angle of mass $m_{B}$ is

θB = 180° + 12° = 192° counterclockwise from mass mA. (i.e. 7.5 kg).

#SPJ3