a rubber ball floats with 3/5th of its volume above the surface of water find the density of the rubber ball density of water is 1 gram centimetre cube
Answers
Answer:
Explanation:
Given A rubber ball floats with 3/5th of its volume above the surface of water find the density of the rubber ball density of water is 1 gram centimetre cube
We know that
Volume of rubber ball above the surface of water = 3 / 5
Therefore, volume of rubber ball below the surface of water = 1 – 3/5
= 2/5
Weight of the water displaced = 2/5
We know that
force of buoyancy = weight of water displaced by ball = 2/5 x volume of ball x density of water x acceleration due to gravity -----------1
Force of buoyancy supports ball in water
Now force of buoyancy = weight of ball only
= volume x density x acceleration due to gravity.---------2
From 1 and 2 we get
Density of ball = 2/5 x density of water
= 2/5 = 0.4 g/cc
Answer:
2/5=0.4g/cc will be the correct answer hope it helps you