Question

A rubber ball is dropped from a height of 5m on a planet, where accelaration due to gravity is nit known. on bouncing, it rises to 1.8m. the ball loses its velocity on bouncing by a factor of

Answer 1

s = 1.8 = 1/2 t^2 
t^2 = 3.6 

t = sqrt(3.6) 


on the "down" path 
s = 5 = 1/2 a * t^2 (a = 1 still) 
10 = t^2 
t=sqrt(10) 

velocity = acc * time 
v = a*t (a = 1 still) 

"up" v = at = sqrt(3.6) 
"down" v = at = sqrt(10) 

the "factor" [ the ball loses its velocity on bouncing?] 

= sqrt(3.6)/sqrt(10) = sqrt (.36) = 0.6 

,,,, my method is scary, but the answer is probly right ... 

good luck