a rubber ball is dropped of 5m on a planet where the acceleration due to gravity is not known on bouncing it rise 1.8m the ball loss it velocity on bouncing by a factor of?
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well acc. is not required as well...
when it's dropped for H=5m:-
as, v^2=u^2+2as ...(a be the acc. due to gravity)
final just before reaching the ground =(2a*5)^1/2...(as u=0)
apply same eq. when it bounces back:-
v^2=u^2+2as
as s=1.8m .... v would have been (2a(1.8))^1/2
thus the loss in velocity is
[(2a(1.8))^1/2] / [2a*5]^1/2
=[1.8/5]^1/2
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