Physics, asked by 1stBrainly, 9 months ago

A rubber cord catapult has crosssectional area 25 mm2 and initial length of rubber cord is 10 cm. It is stretched to 5 cm and then released to project a missile of mass 5 g. Taking Yrubber = 5 × 108 N/m2 , velocity of projected missile is 1) 20 ms–1 2) 100 ms–1 3) 250 ms–1 4) 200 ms–1

Answers

Answered by ReRepeater
2

Answer:

Explanation:

F =kx = YAx/l

PE = 1/2 kx²

   1/2 mv² = 1/2  YAx²/l

            v²  = 625 x 10²

            v =250

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