Question

In a quadrilateral ABCD, angle B =90° = angle D. Prove that
2AC^2 - BC^2 = AB^2 + AD^2 +DC^2

Answer 1

Answer:

I Hope this will help you .

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Given: ABCD is a quadrilateral

and

angle B=90°= angle D

To prove:

In ∆ABC

AC^2=AB^2+BC^2 -------(1)

(by pythagoras)

In ∆DCA

AC^2=DC^2+AD^2 -------(2)

ADD Equation . (1) and (2)

2AC^2 = AB^2+ BC^2+ DC^2+ AD^2

2AC^2 -BC^2=AB^2 + DC^2 + AD^2