Physics, asked by isavij2012, 11 months ago

A runner travels around rectangle track with length = 50 meters and width = 20 meters. After
travels around rectangle track two times, runner back to the starting point. Determine distance
and displacement.

Answers

Answered by madeducators3
111

Given:

A runner travels around rectangle track.

length of track= 50 meters

width of track = 20 meters

runner travels around the rectangle track two times  and finally finishes back at the starting point.

To Find:

Distance and displacement of runner.

Solution:

Distance traveled by runner = 2 (perimeter of rectangle)

Perimeter of rectangle = 2(L+B)

L = 50 m     B = 20 m

perimeter of rectangle = 2(50+20)

                                       = 140 m

Distance traveled by runner = 2 (perimeter of rectangle)

                                                = 280 m

Displacement :

It is the shortest distance between initial and final position or the shortest path of travel

initial position of runner = final position of runner

displacement = 0 m

Distance traveled by runner = 280 m

Displacement traveled by runner = 0 m

Answered by mouliks1018
36

Answer:

Given:

A runner travels around rectangle track.

length of track= 50 meters

width of track = 20 meters

runner travels around the rectangle track two times  and finally finishes back at the starting point.

To Find:

Distance and displacement of runner.

Solution:

Distance traveled by runner = 2 (perimeter of rectangle)

Perimeter of rectangle = 2(L+B)

L = 50 m     B = 20 m

perimeter of rectangle = 2(50+20)

                                       = 140 m

Distance traveled by runner = 2 (perimeter of rectangle)

                                                = 280 m

Displacement :

It is the shortest distance between initial and final position or the shortest path of travel

initial position of runner = final position of runner

displacement = 0 m

Distance traveled by runner = 280 m

Displacement traveled by runner = 0m

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