Question

A running track is enclosed between two concentric circles of radii 40m and 37 m. Find the area of the running track

Answer 1

Answer:

Area of the running track is 725.34 m²

Step-by-step explanation:

According to the question there is a running track with two concentric circles.

Given-:

(i) Radius of the outer circle = 40m

(ii) Radius of the inner circle = 37m

Logic-:

Now in order to find out the area of the track we have to subtract the area of inner circle from the area of outer circle.

So area of outer circle ;

=> πr²

=> 3.14 x (40)²

=> 3.14 x 1600

=> 5024 m²

Area of inner circle ;

=> πr²

=> 3.14 x (37)²

=> 4298.66m²

Required area of the track;

=> [Area of outer circle - area of inner circle]

=> [5024 - 4298.66]m²

=> 725.34 m²

Therefore :-

Area of the running track will be 725.34m².

Answer 2

AnswEr :

⋆ See the Given Attachment :

$\bold{Given} \begin{cases} \scriptsize\underline{\sf{Running \:Track\:Enclosed\:Btw^{n}\:Two\:Concentric\:Circle}} \\ \sf{Radius_1 \: (R)=40 \: m} \\ \sf{Radius_2 \: (r)=37 \: m} \\ \sf{Area \: of \: Running \: Track=?}\end{cases}$

• Area of Running Track Will Be :

⇒ Area = Area of Circle₁ - Area of Circle₂

⇒ Area = πR² - πr²

⇒ Area = π( R² - r² )

⇒ Area = π × [ (40²) - (37)² ]

⇒ Area = π × [ (40 + 37)(40 - 37) ]

⇒ Area = π × ( 77 × 3 )

⇒ Area = $\sf\dfrac{22}{\cancel7}\times\cancel{77}\times3$

⇒ Area = 22 × 11 × 3

⇒ Area = 726 m²

⠀

∴ Area of the Track Will be 726 m².

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⋆ Terms Used Here :

1) a² - b² = (a + b)(a - b)

2) $\pi = \dfrac{22}{7}$

3) Two or more circles which have the same center point are know as Concentric Circle.