Question

A runs at 5/4 th of usual speed and reaches the play ground 5 min earlier.what is usual speed

Answer 1

no bro I am not gives this question answer

Answer 2

Let the usual speed be v
Let the usual time he complete be t
x be the distance to the playground

☆According to Question:
$v = \frac{x}{t}$
$\frac{5v}{4} = \frac{x}{t - 5}$

Solving: we find t by dividing 2 by 1
$\frac{5}{4 } = \frac{t}{t - 5}$
$t = 25$


The usual velocity will be distance divided by 25 metre per second.

The value of distance should be given....