Math, asked by tarshis9mitaaugani, 1 year ago

A's age is 6 times B's age, four years henc3, the age of A will be four times B's age. the present age in years, of A and b are respectively

Answers

Answered by ShivajiK
4
A = 6×B
A+4 = 4×(B+4)
A+4 = 4×B + 16
6×B + 4 = 4×B + 16
6×B - 4×B = 16 - 4
2×B = 12
B = 12÷2
B = 6
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