Math, asked by harshisolanki20, 11 months ago






A's age is half that of B's age. When B's age doubles, what will be the ratio of
B's age to that of A's age

Answers

Answered by Anonymous
1

Answer:same as earlier

Step-by-step explanation:

A:B=1:2

If B age double then,

A:B=2:4=1:2

Answered by MяƖиνιѕιвʟє
4

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Ratio of ages 2:1

\large\red{\underline{\underline{\bf{\blue{Given}}}}}

  • A's age = B's age / 2

\large\red{\underline{\underline{\bf{\blue{To\:Find}}}}}

  • Ratio of B's age to A's age

\large\red{\underline{\underline{\bf{\blue{Solution}}}}}

Let age of B = x years

Then,

According to Question :-

A's age = x/2 years

When B's age doubles then,

B = 2x years

Then,

A's age = 2x/2 = x years

Now,

Ratio of B's age to A's age is

 =  >  \frac{2x}{x}

=> 2:1

Hence,

Ratio of B's age to A's age is 2:1

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